8x^2+8=808

Solution for 8x^2+8=808 equation:

8x^2+8=808

We move all terms to the left:

8x^2+8-(808)=0

We add all the numbers together, and all the variables

8x^2-800=0

a = 8; b = 0; c = -800;
Δ = b2-4ac
Δ = 02-4·8·(-800)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*8}=\frac{-160}{16}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*8}=\frac{160}{16}
=10
$